Rust Error E0507 — Cannot Move Out of a Shared Reference

What Does This Error Mean?

You tried to move a value out of a shared reference (an immutable borrow). Moving would leave the original reference pointing at nothing. Clone the value, or restructure to take ownership instead of borrowing.

Affected Models

Rust stable
Rust nightly
Cargo build
Rust 2021 edition

Common Causes

Calling a method that takes ownership on a value accessed through an immutable reference
Trying to return an owned value from a function that only has a reference to it
Destructuring a reference with a pattern that attempts to move fields out
Using a for loop over a reference to a collection and trying to move elements
Calling .into_iter() on a reference instead of the owned collection

How to Fix It

Clone the value to get an owned copy you can move freely.

Example: let owned = my_ref.clone(); — this creates a new owned value. The type must implement Clone.
Change the function to take ownership instead of a reference.

Change fn foo(x: &MyType) to fn foo(x: MyType) if the caller can give up ownership of the value.
Borrow the value instead of moving it — use a reference where ownership is not needed.

If the receiving function only reads the value, pass a reference to it rather than moving it.
For iteration, iterate over owned values instead of references.

Change for item in &my_vec (which gives references) to for item in my_vec (which moves each element out).
Use .to_owned() or .to_string() for common types like str and String.

my_str_ref.to_owned() converts a str reference into an owned String you can move.

When to Call a Professional

E0507 is a compile-time error safe to fix yourself. It usually reveals an ownership design issue. A Rust expert can help redesign the ownership flow if cloning is too expensive.

Frequently Asked Questions

What is the difference between E0505 and E0507?

E0505 means you tried to move a value while an active borrow of that same value exists. E0507 means you tried to move a value out through a reference — the reference itself prevents the move. Both are borrow checker errors; E0507 specifically involves moving through an existing reference.

Why can Rust not just copy the value instead of moving?

Rust only copies types that implement the Copy trait — simple types like integers and booleans. For heap-allocated types like String and Vec, copying requires an explicit .clone() call. This design makes performance costs visible — you always know when a heap allocation happens.

When is cloning too expensive and what should I do instead?

Cloning a large Vec or complex struct copies all the heap data — this can be slow in tight loops. Instead, redesign the ownership so the consumer takes ownership from the start. Or use Arc<T> to share the data between multiple owners without copying.